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NotesShala Class 11 · Physics
Chapter01

Units and Measurements

System of Units · Significant Figures & Rounding Off · Dimensions of a Physical Quantity

Reading key Definition Note Remember Derivation Strategy Formulas sit on graph paper · coloured words are the key terms
01
Part 1

System of Units

Definition
System of Units

A few quantities are chosen first, and each one is given its own unit. These units are called base (or fundamental) units. All other units are made by multiplying or dividing powers of the base units. They are called derived units. The complete set of base units and derived units is called a system of units.

1.1Physical Quantities

A quantity that can be measured is called a physical quantity. It is measured directly with an instrument or found by calculation. The laws of physics are written using these quantities. Examples: length, mass, speed and force. Physical quantities are of two types:

iFundamental Quantities

These quantities are not defined using any other quantity. They are independent. They are also called base quantities.

e.g. Mass, length, time, temperature, electric current, luminous intensity and amount of substance.

iiDerived Quantities

These quantities are made from the fundamental quantities by multiplying or dividing them.

e.g. Velocity (length ÷ time), acceleration and linear momentum.

1.2Measurement of Physical Quantities

Measurement means comparing a quantity with a fixed standard of the same kind. This fixed standard is called the unit. So every measurement has two parts:

1Unit (u)(u)

The standard that the quantity is compared with. For example, the metre, the second or the kilogram.

2Numerical Value (n)(n)

The number written before the unit. It tells how many times the unit (u)(u) is contained in the quantity.

Note
Smaller Unit, Bigger Number

For the same quantity, the numerical value (n)(n) is inversely proportional to the size of the unit (u)(u):

n∝1u⇒nu=constantn \propto \dfrac{1}{u}\quad\Rightarrow\quad nu = \text{constant}

e.g. the same length written in three different units:

in metre (m)→n = 1largest unit
in centimetre (cm)→n = 100
in millimetre (mm)→n = 1000smallest unit

KeyA smaller unit (u ↓) gives a bigger number (n ↑). The product n · u never changes

Changing the unit does not change the quantity itself. Let n1n_1 and n2n_2 be the numerical values of the same quantity in units u1u_1 and u2u_2. Then n1u1=n2u2n_1u_1 = n_2u_2.

Physical Quantity Q=nuQ = nu

QQ = physical quantity, nn = numerical value, uu = unit

1.3Physical Unit

Definition

A physical unit is a fixed standard amount of a quantity. It is used to measure other amounts of the same kind of quantity.

A good unit must meet a few basic requirements:

What Makes a Good Unit
  • It should be of a convenient size. It should not be too large or too small for everyday use.
  • It should be easily available to anyone who needs it.
  • It should not change with time.
  • It should be easy to reproduce anywhere in the world.
  • It should not change with physical conditions such as pressure, volume or temperature.

Units are of two types:

iFundamental Units

These units cannot be obtained from one another. They cannot be broken down into simpler units. They are the units of fundamental quantities, such as length, mass and time. They are also called base units.

iiDerived Units

These are the units of all other quantities. They are formed by combining fundamental units.

e.g. Speed is distance divided by time. So its unit is made from the units of distance and time. It is a derived unit:

Speed=DistanceTime∴ Unit of speed=Unit of distanceUnit of time=ms=ms−1\begin{aligned}\text{Speed} &= \dfrac{\text{Distance}}{\text{Time}} \\[3pt] \therefore\ \text{Unit of speed} &= \dfrac{\text{Unit of distance}}{\text{Unit of time}} \\[3pt] &= \dfrac{\text{m}}{\text{s}} = \text{ms}^{-1}\end{aligned}

1.4The International System of Units

A system of units gives units for all physical quantities, both fundamental and derived. Different systems have been used over the years. The most common ones in mechanics are:

iFPS System

It is the British engineering system. It measures length in foot, mass in pound and time in second.

iiCGS System

It is also called the Gaussian system. It measures length in centimetre, mass in gram and time in second.

iiiMKS System

It measures length in metre, mass in kilogram and time in second.

ivInternational System of Units (SI Units)

SI is short for Système International d'Unités. This French name means International System of Units. It is the system accepted all over the world. The General Conference on Weights and Measures adopted it in 1960. In 1971, the mole was added as its seventh base unit. It gives one standard set of symbols, units and abbreviations for science, technology, industry and trade.

Note

SI was developed from the MKS system. So it is also called the rationalised MKS system. It has units for every physical quantity used in physics.

1.5SI Base Quantities and Units

SI has seven base units. It also has two supplementary units for measuring angles.

The Seven Base Units at a Glance
Lengthmmetre
Masskgkilogram
Timessecond
Electric currentAampere
Thermodynamic temperatureKkelvin
Amount of substancemolmole
Luminous intensitycdcandela
Formal Definitions (since 2019)
Base quantityNameSymbolDefinition
LengthMetremFixed by the speed of light: cc is exactly 299 792 458 m s−1299\,792\,458\ \text{m s}^{-1}. So one metre is the distance light travels in vacuum in 1299 792 458\tfrac{1}{299\,792\,458} of a second. 2019Same meaning as the 1983 definition.
MassKilogramkgFixed by the Planck constant: hh is exactly 6.626 070 15×10−34 J s6.626\,070\,15\times10^{-34}\ \text{J s}, where J s=kg m2s−1\text{J s}=\text{kg m}^2\text{s}^{-1}. With the metre and the second already fixed, this sets the kilogram. 2019Earlier (1889–2019): the mass of a platinum–iridium cylinder kept near Paris.
TimeSecondsFixed by the caesium-133 atom: the frequency of its hyperfine transition, ΔνCs\Delta\nu_{\text{Cs}}, is exactly 9 192 631 7709\,192\,631\,770 Hz. So one second is the time taken by 9 192 631 7709\,192\,631\,770 periods of that radiation. 2019Same meaning as the 1967 definition.
Electric currentAmpereAFixed by the elementary charge: ee is exactly 1.602 176 634×10−191.602\,176\,634\times10^{-19} C, where C = A s. So a current of 1 A carries about 6.24×10186.24\times10^{18} elementary charges every second. 2019Earlier (1948–2019): defined by the force between two long, parallel current-carrying wires.
Thermodynamic temperatureKelvinKFixed by the Boltzmann constant: kk is exactly 1.380 649×10−23 J K−11.380\,649\times10^{-23}\ \text{J K}^{-1} (here 1 J=1 kg m2s−21\ \text{J}=1\ \text{kg m}^2\text{s}^{-2}). 2019Earlier (1967–2019): 1273.16\tfrac{1}{273.16} of the thermodynamic temperature of the triple point of water.
Amount of substanceMolemolOne mole contains exactly 6.022 140 76×10236.022\,140\,76\times10^{23} elementary entities (atoms, molecules, ions, …). This number is the Avogadro constant NAN_A, expressed in mol−1\text{mol}^{-1}. 2019Earlier (1971–2019): as many entities as there are atoms in 0.012 kg of carbon-12.
Luminous intensityCandelacdFixed by the luminous efficacy KcdK_{\text{cd}} of monochromatic light of frequency 540×1012540\times10^{12} Hz, which is exactly 683 lm W−1683\ \text{lm W}^{-1}. 2019Same meaning as the 1979 definition (radiant intensity of 1683\tfrac{1}{683} watt per steradian).
Good to Know
What Changed in 2019?

Since 20 May 2019, every SI base unit is defined using a constant of nature. Each constant is given an exact, fixed value. Now no unit depends on a physical object. Earlier, the kilogram was defined by a metal cylinder. This cylinder could get scratched or slowly change. Today the kilogram can be reproduced anywhere in the world from the Planck constant.

ΔνCs\Delta\nu_{\text{Cs}}→ second cc→ metre hh→ kilogram ee→ ampere kk→ kelvin NAN_A→ mole KcdK_{\text{cd}}→ candela
Definition
Two Supplementary Quantities

Apart from the seven base quantities, SI has two supplementary quantities for measuring angles. These are the plane angle and the solid angle.

Plane AngleRadian · rad

One radian is the angle made at the centre of a circle by an arc whose length is equal to the radius.

dθ=dsrd\theta=\dfrac{ds}{r}
O r s θ
Arc ss makes a plane angle θ\theta at the centre OO
Solid AngleSteradian · sr

One steradian is the solid angle made at the centre of a sphere by a part of its surface whose area is equal to the square of the radius.

dΩ=dAr2d\Omega=\dfrac{dA}{r^{2}}
O r Ω A
Surface area AA makes a solid angle Ω\Omega at the centre OO
Note
  • The FPS system is not a metric system. It is rarely used today.
  • The CGS system has a weakness. Many of its derived units are too small to be convenient.
  • The MKS system has an advantage. Many of its derived units are of a practical size.

1.6SI Derived Units with Special Names

Many derived units have special names. Most of them are named in honour of famous scientists. The common ones are:

Physical QuantityNameSymbolIn terms of other unitsIn terms of SI base units
FrequencyHertzHz–s−1\text{s}^{-1}
ForceNewtonN–kg m s−2\text{kg m s}^{-2}
Pressure, stressPascalPaN/m2\text{N/m}^2 or N m−2\text{N m}^{-2}kg m−1s−2\text{kg m}^{-1}\text{s}^{-2}
Energy, work, quantity of heatJouleJN mkg m2s−2\text{kg m}^{2}\text{s}^{-2}
Power, radiant fluxWattWJ/s or J s−1^{-1}kg m2s−3\text{kg m}^{2}\text{s}^{-3}
Quantity of electricity, electric chargeCoulombC–A s
Electric potential, potential difference, EMFVoltVW/A or W A−1^{-1}kg m2s−3A−1\text{kg m}^{2}\text{s}^{-3}\text{A}^{-1}
CapacitanceFaradFC/VA2s4kg−1m−2\text{A}^{2}\text{s}^{4}\text{kg}^{-1}\text{m}^{-2}
Electric resistanceOhmΩ\OmegaV/Akg m2s−3A−2\text{kg m}^{2}\text{s}^{-3}\text{A}^{-2}
ConductanceSiemensSA/Vm−2kg−1s3A2\text{m}^{-2}\text{kg}^{-1}\text{s}^{3}\text{A}^{2}
Magnetic fluxWeberWbV s or J/Akg m2s−2A−1\text{kg m}^{2}\text{s}^{-2}\text{A}^{-1}
Magnetic field, flux density, inductionTeslaTWb/m2^2kg s−2A−1\text{kg s}^{-2}\text{A}^{-1}
InductanceHenryHWb/Akg m2s−2A−2\text{kg m}^{2}\text{s}^{-2}\text{A}^{-2}
Luminous flux, luminous powerLumenlm–cd sr
IlluminanceLuxlxlm/m2^2m−2cd sr\text{m}^{-2}\text{cd sr}
Activity (of a radio nuclide / radioactive source)BecquerelBq–s−1\text{s}^{-1}
Absorbed dose, absorbed dose indexGrayGyJ/kgm2s−2\text{m}^{2}\text{s}^{-2}

1.7Some SI Derived Units Expressed by Means of SI Units

Other derived units have no special name. They are simply written as a combination of SI units. Useful examples:

Physical quantityNameSymbolIn terms of SI base units
Magnetic momentJoule per teslaJ T−1^{-1}m2A\text{m}^{2}\text{A}
Dipole momentCoulomb metreC ms A m
Dynamic viscosityPoiseuille or pascal second or newton second per square metrePl or Pa s or N s/m2^2m−1kg s−1\text{m}^{-1}\text{kg s}^{-1}
Torque, couple, moment of forceNewton metreN mm2kg s−2\text{m}^{2}\text{kg s}^{-2}
Surface tensionNewton per metreN/mkg s−2\text{kg s}^{-2}
Power density, irradiance, heat flux densityWatt per square metreW/m2^2kg s−3\text{kg s}^{-3}
Heat capacity, entropyJoule per kelvinJ/Km2kg s−2K−1\text{m}^{2}\text{kg s}^{-2}\text{K}^{-1}
Specific heat capacity, specific entropyJoule per kilogram kelvinJ/kg Km2s−2K−1\text{m}^{2}\text{s}^{-2}\text{K}^{-1}
Specific energy, latent heatJoule per kilogramJ/kgm2s−2\text{m}^{2}\text{s}^{-2}
Radiant intensityWatt per steradianW sr−1^{-1}m2kg s−3sr−1\text{m}^{2}\text{kg s}^{-3}\text{sr}^{-1}
Thermal conductivityWatt per metre kelvinW m−1^{-1}K−1^{-1}m kg s−3K−1\text{m kg s}^{-3}\text{K}^{-1}
Energy densityJoule per cubic metreJ/m3^3kg m−1s−2\text{kg m}^{-1}\text{s}^{-2}
Electric field strengthVolt per metreV/mm kg s−3A−1\text{m kg s}^{-3}\text{A}^{-1}
Electric charge densityCoulomb per cubic metreC/m3^3m−3A s\text{m}^{-3}\text{A s}
Electric flux densityCoulomb per square metreC/m2^2m−2A s\text{m}^{-2}\text{A s}
PermittivityFarad per metreF/mm−3kg−1s4A2\text{m}^{-3}\text{kg}^{-1}\text{s}^{4}\text{A}^{2}
PermeabilityHenry per metreH/mm kg s−2A−2\text{m kg s}^{-2}\text{A}^{-2}
Molar energyJoule per moleJ/molm2kg s−2mol−1\text{m}^{2}\text{kg s}^{-2}\text{mol}^{-1}
Angular momentum, Planck constantJoule secondJ skg m2s−1\text{kg m}^{2}\text{s}^{-1}
Molar entropy, molar heat capacityJoule per mole kelvinJ/mol Km2kg s−2K−1mol−1\text{m}^{2}\text{kg s}^{-2}\text{K}^{-1}\text{mol}^{-1}
Exposure (X-rays and γ\gamma-rays)Coulomb per kilogramC/kgkg−1s A\text{kg}^{-1}\text{s A}
Absorbed dose rateGray per secondGy/sm2s−3\text{m}^{2}\text{s}^{-3}
CompressibilityPer pascalPa−1^{-1}m kg−1s2\text{m kg}^{-1}\text{s}^{2}
Elastic moduliNewton per square metreN/m2^2 or N m−2^{-2}kg m−1s−2\text{kg m}^{-1}\text{s}^{-2}
Pressure gradientPascal per metrePa/m or N m−3^{-3}kg m−2s−2\text{kg m}^{-2}\text{s}^{-2}
Surface potentialJoule per kilogramJ/kg or N m/kgm2s−2\text{m}^{2}\text{s}^{-2}
Pressure energyPascal cubic metrePa m3^3 or N mkg m2s−2\text{kg m}^{2}\text{s}^{-2}
ImpulseNewton secondN skg m s−1\text{kg m s}^{-1}
Angular impulseNewton metre secondN m skg m2s−1\text{kg m}^{2}\text{s}^{-1}
Specific resistanceOhm metreΩ\Omega mkg m3s−3A−2\text{kg m}^{3}\text{s}^{-3}\text{A}^{-2}
Surface energyJoule per square metreJ/m2^2 or N/mkg s−2\text{kg s}^{-2}

1.8Advantages of SI over Other Systems of Units

iCoherent System

Every derived unit is obtained from the base units by simple multiplication or division. No extra numerical factors are needed.

iiRational System

It has only one unit for each quantity. For example, all forms of energy are measured in joule.

iiiMetric System

Larger and smaller units are formed using powers of 10, i.e. a×10±ba\times10^{\pm b}. This makes conversion between them easy.

ivAbsolute System

It does not use gravitational units. So its definitions do not depend on the value of gg.

1.9Some General Units & Unit Conversion

Some General Units (Outside SI)
NameSymbolValue in SI Unit
Minutemin60 s
Hourh60 min = 3600 s
Dayd24 h = 86400 s
Yeary365.25365.25 d =3.156×107= 3.156\times10^{7} s
Degree∘^\circ1∘=(π/180)1^\circ=(\pi/180) rad
LitreL1 dm3=10−3 m31\,\text{dm}^3=10^{-3}\,\text{m}^3
Tonnet10310^{3} kg
Caratc200 mg
Barbar0.10.1 MPa =105=10^{5} Pa
CurieCi3.7×1010 s−13.7\times10^{10}\,\text{s}^{-1}
RoentgenR2.58×10−42.58\times10^{-4} C/kg
Quintalq100 kg
Barnb100 fm2=10−28 m2100\,\text{fm}^2=10^{-28}\,\text{m}^2
Area1 dam2=102 m21\,\text{dam}^2=10^{2}\,\text{m}^2
Hectareha1 hm2=104 m21\,\text{hm}^2=10^{4}\,\text{m}^2
Standard atmospheric pressureatm101325101325 Pa =1.013×105=1.013\times10^{5} Pa
Problem Solving Strategy
Unit Conversion
  1. Find what is needed. Note the given units and the units asked for. First convert everything to SI units (metre, kilogram, second). This usually makes the problem easiest.
  2. Write the conversion factors. Units can be multiplied and divided like algebraic symbols. A factor such as 60 s1 min\dfrac{60\ \text{s}}{1\ \text{min}} is equal to 1. So multiplying by it changes the unit but not the quantity.
  3. Multiply and cancel. Multiply the quantity by the factors. Cancel the same units until only the required unit is left.
  4. Check the result. The answer should be in the unit asked for. The size of the number should be reasonable.

1.10Rules for Writing SI Units

1Rule 1

Unit symbols are normally written in small (lower-case) letters. Examples: m, kg, s.

2Rule 2

A symbol is never followed by a full stop. Write “5 kg”, not “5 kg.” with a dot.

3Rule 3

A symbol begins with a capital letter only when the unit is named after a scientist. Examples: N, Pa, J.

4Rule 4

A unit written in full always begins with a small letter. This is true even if it is named after a scientist. Examples: newton, joule.

5Rule 5

Symbols have no plural form. Write 10 kg, not 10 kgs.

1.11Abbreviations in Powers of Ten

Very large and very small values are easier to write using prefixes. Each prefix stands for a power of ten. It gives a convenient multiple or sub-multiple of the SI unit:

MultiplePrefixSymbolSub-multiplePrefixSymbol
10110^{1}decada10−110^{-1}decid
10210^{2}hectoh10−210^{-2}centic
10310^{3}kilok10−310^{-3}millim
10610^{6}megaM10−610^{-6}microμ\mu
10910^{9}gigaG10−910^{-9}nanon
101210^{12}teraT10−1210^{-12}picop
101510^{15}petaP10−1510^{-15}femtof
101810^{18}exaE10−1810^{-18}attoa
Examples
1 megaohmMΩ=106 Ω\text{M}\Omega=10^{6}\,\Omega
1 milliampere1 mA=10−3 A1\,\text{mA}=10^{-3}\,\text{A}
1 kilometre1 km=103 m1\,\text{km}=10^{3}\,\text{m}
1 microvolt1 μV=10−6 V1\,\mu\text{V}=10^{-6}\,\text{V}
1 decagram1 dag=10 g1\,\text{dag}=10\,\text{g}
1 nanosecond1 ns=10−9 s1\,\text{ns}=10^{-9}\,\text{s}
1 centimetre1 cm=10−2 m1\,\text{cm}=10^{-2}\,\text{m}
1 picofarad1 pF=10−12 F1\,\text{pF}=10^{-12}\,\text{F}
Note
Why CGS, MKS and SI Are "Decimal" Systems

In CGS, MKS and SI, the larger and smaller units are related to the basic units by powers of 10. That is why they are called metric or decimal systems of units.

1.12Some Important Practical Units

Some quantities are very large or very small. For them, special practical units are more convenient than SI units. They are grouped below by the quantity they measure:

For Length / Distance
Astronomical / Large Distances
Astronomical Unit (AU)The average distance between the Earth and the Sun.1 AU=1.496×1011 m1\,\text{AU}=1.496\times10^{11}\,\text{m}
Light Year (ly)The distance light travels in vacuum in one year.1 ly=9.46×1015 m1\,\text{ly}=9.46\times10^{15}\,\text{m}
Parallactic second (parsec)The distance at which an arc of 1 AU makes an angle of one second of arc.1 parsec=3.084×1016 m=3.26 ly1\,\text{parsec}=3.084\times10^{16}\,\text{m}=3.26\,\text{ly}
Sub-microscopic / Small Distances
Micron / micrometre1 μm=10−6 m1\,\mu\text{m}=10^{-6}\,\text{m}
Nanometre1 nm=10−9 m1\,\text{nm}=10^{-9}\,\text{m}
Angstrom unit (Å)1 A˚=10−10 m1\,\text{\AA}=10^{-10}\,\text{m}
FermiUsed for the sizes of nuclei.1 fm=10−15 m1\,\text{fm}=10^{-15}\,\text{m}
For Mass
Conventional / Large Masses
Pound1 lb=0.4536 kg1\,\text{lb}=0.4536\,\text{kg}
Slug1 slug=14.59 kg1\,\text{slug}=14.59\,\text{kg}
Quintal1 q=100 kg1\,\text{q}=100\,\text{kg}
Tonne / Metric ton1 t=1000 kg1\,\text{t}=1000\,\text{kg}
Atomic Scale
Atomic mass unit (amu)One-twelfth (112\tfrac{1}{12}) of the mass of one 6C12_{6}\text{C}^{12} atom.1 amu=1.66×10−27 kg1\,\text{amu}=1.66\times10^{-27}\,\text{kg}
For Time
Astronomical & Calendar Units
Solar dayThe time the Earth takes to rotate once on its own axis, measured with respect to the Sun.
Sidereal dayThe time the Earth takes to rotate once on its own axis, measured with respect to a distant star.
Solar yearThe time the Earth takes to go once around the Sun in its orbit. 11 solar year =365.25=365.25 average solar days =366.25=366.25 sidereal days.
Tropical yearThe time from one spring (vernal) equinox to the next. It is about 365.24365.24 days. Our calendar year is based on it.
Leap yearA year divisible by 4, in which February has 29 days. A century year must be divisible by 400.
Lunar monthThe time the Moon takes to go once around the Earth.1 lunar month=27.3 days1\text{ lunar month}=27.3\text{ days}
Smallest Practical Unit
ShakeThe smallest practical unit of time.1 shake=10−8 s1\,\text{shake}=10^{-8}\,\text{s}
For Areas
Barn1 barn=10−28 m21\,\text{barn}=10^{-28}\,\text{m}^2
Acre1 acre=4047 m21\,\text{acre}=4047\,\text{m}^2
Hectare1 hectare=104 m21\,\text{hectare}=10^{4}\,\text{m}^2
For Other Quantities
Volume
LitreHere cc means cubic centimetre (cm3^3).1 L=103 cc=10−3 m31\,\text{L}=10^{3}\,\text{cc}=10^{-3}\,\text{m}^3
GallonUSA: 11 gallon =3.7854 L=3.7854\,\text{L}; UK: 11 gallon =4.546 L=4.546\,\text{L}.
Pressure
PascalAtmospheric pressure is about 1 atm=1.01×105 Pa1\,\text{atm}=1.01\times10^{5}\,\text{Pa}.1 Pa=1 N m−21\,\text{Pa}=1\,\text{N m}^{-2}
BarVery close to atmospheric pressure (1 atm≈1.0131\,\text{atm}\approx1.013 bar).1 bar=105 Pa1\,\text{bar}=10^{5}\,\text{Pa}
TorrThe pressure of a 1 mm column of mercury.1 torr=133.3 Pa1\,\text{torr}=133.3\,\text{Pa}
Energy / Work
Electron volt1 eV=1.6×10−19 J1\,\text{eV}=1.6\times10^{-19}\,\text{J}
Erg1 erg=10−7 J1\,\text{erg}=10^{-7}\,\text{J}
Kilowatt hour1 kWh=3.6×106 J1\,\text{kWh}=3.6\times10^{6}\,\text{J}
Power, Optics & Angle
Horse power1 HP=746 W1\,\text{HP}=746\,\text{W}
DioptreUnit of the power of a lens.1 D=1 m−11\,\text{D}=1\,\text{m}^{-1}
DegreeUnit of plane angle.1∘=(π/180) rad1^\circ=(\pi/180)\,\text{rad}
02
Part 2

Significant Figures & Rounding Off

Definition
Significant Figures

Every measured value has some digits that are certain. They are followed by one last digit, which is only an estimate. The reliable digits and this first uncertain digit together are called the significant figures (or significant digits) of the measurement.

Reading a Measurement · 374.5 m
374
Certain & reliable
.
5
Uncertain (estimated)
m
= 4 significant figures

The digits 3, 7 and 4 are certain. The last digit, 5, is estimated. Any more digits would add no real information.

2.1Rules for Determining Significant Figures

significant not significant

1Rule 1

Every non-zero digit is significant.

1234→4 S.F.
2Rule 2

Zeros between non-zero digits are always significant. It does not matter where the decimal point is, or if there is none.

1007→4 S.F.
100.7→4 S.F.
3Rule 3

In a number smaller than one, the zeros after the decimal point but before the first non-zero digit are not significant.

0.005704→4 S.F.
4Rule 4

In a number without a decimal point, the trailing zeros (zeros at the end) are not significant.

3210→3 S.F.
5Rule 5

In a number with a decimal point, the trailing zeros are significant.

3.500→4 S.F.
6Rule 6

Exact numbers have unlimited significant figures. They are pure numbers used to multiply or divide. They are not measured or rounded.
e.g. In r=d2r=\dfrac{d}{2} and s=2πrs=2\pi r, the factor 2 is exact. It can be treated as 2.0, 2.00, 2.000 and so on.

2→∞ S.F. (exact)
7Rule 7

Changing the unit never changes the number of significant figures. For example, 16.416.4 cm, 0.1640.164 m and 0.0001640.000164 km all have three.

16.4cm→3 S.F.
0.164m→3 S.F.
0.000164km→3 S.F.

2.2Ambiguity & Scientific Notation

Remember
Ambiguity in Significant Figures

Trailing zeros can cause confusion. Suppose a length is measured as x=4.700x=4.700 m. Here the zeros show the precision of the measurement. So they are significant. The same length can also be written as x=0.004700x=0.004700 km, x=470.0x=470.0 cm or x=4700x=4700 mm.

By Rule 4, 47004700 mm would wrongly seem to have only two significant figures. But 0.0047000.004700 km clearly shows four. Changing units cannot change the number of significant figures (Rule 7). So we need a clearer way to write such values.

The Same Length, Four Ways · x = 4.700 m
4.700m→4 S.F.
0.004700km→4 S.F.
470.0cm→4 S.F.
4700mm→looks like 2 S.F.? — ambiguous!

The length is the same in every line. But 4700 mm seems to have only two significant figures. The solution:

Write every measurement in scientific notation, i.e. in powers of 10. Any number can be written in the form:

Scientific Notation a×10ba \times 10^{b}

aa = a number between 1 and 10,   bb = a positive or negative power of 10 (the order of magnitude)

e.g. x=4.700x=4.700 m =4.700×10−3=4.700\times10^{-3} km has 4 significant figures. The power of 10 is not counted.

2.3Rounding Off

A result calculated from approximate values often has too many uncertain digits. So it is rounded off. The usual rules are:

1Rule 1

If the digit to be dropped is less than 5, keep the digit before it unchanged.

7.82→7.8
2Rule 2

If the digit to be dropped is more than 5, increase the digit before it by one.

6.87→6.9
3Rule 3

If the digit to be dropped is 5 followed by non-zero digits, increase the digit before it by one.

16.351→16.4
4Rule 4

If the digit to be dropped is 5, or 5 followed only by zeros, keep the digit before it unchanged if it is even.

3.250→3.2(2 is even)
5Rule 5

If the digit to be dropped is 5, or 5 followed only by zeros, increase the digit before it by one if it is odd.

3.750→3.8(7 is odd)

2.4Rules for Arithmetical Operations with Significant Figures

Measured values that we add, subtract, multiply or divide may have different precisions. The answer can never be more precise than the least precise value used. So we round it using these rules:

Addition and Subtraction

Keep as many decimal places as the value that has the fewest decimal places.

RuleRound the answer to the fewest decimal places

2.11 d.p.+1.78+2.046=5.926 m\underset{\text{1 d.p.}}{2.1} + 1.78 + 2.046 = 5.926\text{ m}
round →5.9 m1 d.p. (set by 2.1)

Similarly, for x=12.587x=12.587 m and y=12.51 d.p.y=\underset{\text{1 d.p.}}{12.5} m:

x−y=12.587−12.5=0.087 mx-y = 12.587 - 12.5 = 0.087\text{ m}
round →0.1 m1 d.p. (set by 12.5)
Multiplication and Division

Keep as many significant figures as the value that has the fewest significant figures.

RuleRound the answer to the fewest significant figures

e.g. The speed of light is 3.003 S.F.×108\underset{\text{3 S.F.}}{3.00}\times10^{8} m/s. One year is 3.1557×1073.1557\times10^{7} s. So one light year is:

3.00×108×3.1557×107=9.4671×1015 m3.00\times10^{8}\times3.1557\times10^{7} = 9.4671\times10^{15}\text{ m}
round →9.47×10159.47\times10^{15} m3 S.F. (set by 3.00)

2.5Rules for Determining Uncertainty in the Results of Arithmetic Calculations

1Rule 1 · Product (Combining Percentage Errors)

A thin rectangular sheet is 15.415.4 cm long and 10.210.2 cm wide. Both values have three significant figures. They are precise to the first decimal place (±0.1 cm).

  1. Convert each absolute error into a percentage error:

    l=(15.4±0.1) cm=15.4 cm±(0.115.4×100)%=15.4 cm±0.6%l=(15.4\pm0.1)\text{ cm}=15.4\text{ cm}\pm\left(\dfrac{0.1}{15.4}\times100\right)\% = 15.4\text{ cm}\pm0.6\%
    b=(10.2±0.1) cm=10.2 cm±(0.110.2×100)%=10.2 cm±1%b=(10.2\pm0.1)\text{ cm}=10.2\text{ cm}\pm\left(\dfrac{0.1}{10.2}\times100\right)\% = 10.2\text{ cm}\pm1\%
  2. For a product, the percentage errors are added:

    A=15.4×10.2±(0.6+1.0)%=157.08 cm2±1.6%=(157.08±2.51) cm2A = 15.4\times10.2 \pm(0.6+1.0)\% = 157.08\text{ cm}^2 \pm1.6\% = (157.08\pm2.51)\text{ cm}^2
  3. Keep 3 S.F. in the area and 1 S.F. in its error:

    A=(157±3) cm2A=(157\pm3)\text{ cm}^2
2Rule 2 · Result Retains the Significant Figures of the Data

If the data has nn significant figures, the result can be trusted only up to nn significant figures.

e.g. x=13.7x=13.7 m and y=8.08y=8.08 m each have three significant figures:

x−y=13.7−8.08=5.62 mx-y = 13.7-8.08 = 5.62\text{ m}
round →5.6 mkeep the fewest decimal places (1 d.p., set by 13.7)
3Rule 3 · Relative Error Depends on the Number Itself

The relative error of a value depends on its number of significant figures. It also depends on the size of the number. For example, m1=(1.04±0.01)m_1=(1.04\pm0.01) kg and m2=(9.24±0.01)m_2=(9.24\pm0.01) kg have the same absolute error of 0.010.01 kg:

1.041.04 kg→±0.011.04×100\pm\dfrac{0.01}{1.04}\times100=±1%\pm1\%
9.249.24 kg→±0.019.24×100\pm\dfrac{0.01}{9.24}\times100=±0.1%\pm0.1\%

InsightLarger value ⇒ smaller relative error

4Rule 4 · Keep One Extra Digit in Multi-Step Calculations

In a calculation with several steps, round off only at the end. In the middle steps, keep one more significant figure than the least precise measurement has.

e.g. Start with x=9.58x=9.58. Find 1x\dfrac{1}{x}. Then take the reciprocal again. Do we get 9.589.58 back?

✗  Keep 3 digits
19.58=0.104\dfrac{1}{9.58}=0.104
10.104=9.62\dfrac{1}{0.104}=9.62

≠9.58\neq 9.58 — an error appears

✓  Keep 4 digits
19.58=0.1044\dfrac{1}{9.58}=0.1044
10.1044=9.58\dfrac{1}{0.1044}=9.58

=9.58=9.58 — correct

Keeping one extra digit in the middle steps stops rounding errors from growing.

03
Part 3

Dimensions of a Physical Quantity

Definition
Dimensions of a Physical Quantity

The dimensions of a physical quantity are the powers to which the base quantities must be raised to express that quantity. Each of the seven base quantities has its own dimension symbol. It is written inside square brackets [ ]:

[L]Length [M]Mass [T]Time [A]Electric current [K]Temperature [cd]Luminous intensity [mol]Amount of substance
Example · Volume

Volume is length × length × length:

V=[L]×[L]×[L]=[L3]V = [\text{L}]\times[\text{L}]\times[\text{L}] = [\text{L}^3]

It has no mass and no time. So   V=[M0L3T0]\;V = \mathbf{[\text{M}^0\text{L}^3\text{T}^0]}.

Example · Force

Force is mass × acceleration:

F=mass×acceleration=mass×length(time)2F = \text{mass}\times\text{acceleration} = \text{mass}\times\dfrac{\text{length}}{(\text{time})^2}

∴  F=[M][L][T2]=[MLT−2]\therefore\; F = \dfrac{[\text{M}][\text{L}]}{[\text{T}^2]} = \mathbf{[\text{MLT}^{-2}]}

Note

Square brackets [  ][\;] around a quantity show its dimensions, not its value.

3.1Dimensional Formulae & Dimensional Equations

Definition
Dimensional Formula

An expression that shows the base quantities in a physical quantity and their powers is called its dimensional formula.

e.g. powers colour-coded by base quantity — M mass, L length, T time:

Acceleration[M0 L1 T−2][\textcolor{#0a7d73}{\text{M}^0}\,\textcolor{#1f5fcf}{\text{L}^1}\,\textcolor{#6a3fcf}{\text{T}^{-2}}]
Mass density[M1 L−3 T0][\textcolor{#0a7d73}{\text{M}^1}\,\textcolor{#1f5fcf}{\text{L}^{-3}}\,\textcolor{#6a3fcf}{\text{T}^0}]
Volume[M0 L3 T0][\textcolor{#0a7d73}{\text{M}^0}\,\textcolor{#1f5fcf}{\text{L}^3}\,\textcolor{#6a3fcf}{\text{T}^0}]
Definition
Dimensional Equation

When a physical quantity is written equal to its dimensional formula, we get its dimensional equation.

e.g. each line shows the quantity, how it is defined, and its dimensions:

Linear momentum== mass ×\times velocity =[M1L1T−1]=[\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^{-1}}]
Impulse== force ×\times time =[M1L1T−1]=[\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^{-1}}]
Moment of inertia== mass ×\times (radius of gyration)2=[M1L2T0]^2=[\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^2}\textcolor{#6a3fcf}{\text{T}^0}]
Problem Solving Strategy
Finding Dimensional Formulae
  1. Read the question and note whether a formula or a law for the quantity is given.
  2. Write down the defining formula of the quantity whose dimensions you need.
  3. Write that formula in terms of fundamental quantities, e.g. acceleration =LengthTime2=\dfrac{\text{Length}}{\text{Time}^2}.
  4. Replace each fundamental quantity by its symbol: mass =[M]=[\text{M}], length =[L]=[\text{L}], time =[T]=[\text{T}], and so on.
  5. Simplify the powers algebraically to get the result.
  6. Write the answer in the standard order [M], [L], [T] …[\text{M}],\,[\text{L}],\,[\text{T}]\,\ldots

3.2Dimensional Formulae of Some Important Quantities

Dimensional formulae are colour-coded by base quantity — M mass, L length, T time, A current.

Physical quantityRelation with other quantitiesDimensional formulaSI unit
Arealength ×\times breadth[M0L2T0][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^2}\textcolor{#6a3fcf}{\text{T}^0}]m2\text{m}^2
Volumelength ×\times breadth ×\times height[M0L3T0][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^3}\textcolor{#6a3fcf}{\text{T}^0}]m3\text{m}^3
Densitymass / volume[M1L−3T0][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^{-3}}\textcolor{#6a3fcf}{\text{T}^0}]kg m−3\text{kg m}^{-3}
Specific gravitydensity of body / density of water at 4°C[M0L0T0][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^0}\textcolor{#6a3fcf}{\text{T}^0}] (dimensionless)no units
Speed or velocitydistance / time[M0L1T−1][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^{-1}}]m s−1\text{m s}^{-1}
Linear momentummass ×\times velocity[M1L1T−1][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^{-1}}]kg m s−1\text{kg m s}^{-1}
Accelerationchange in velocity / time[M0L1T−2][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^{-2}}]m s−2\text{m s}^{-2}
Acceleration due to gravity (g)(g)change in velocity / time[M0L1T−2][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^{-2}}]m s−2\text{m s}^{-2}
Forcemass ×\times acceleration[M1L1T−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^{-2}}]N (newton)
Impulseforce ×\times time[M1L1T−1][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^{-1}}]N s
Pressureforce / area[M1L−1T−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^{-1}}\textcolor{#6a3fcf}{\text{T}^{-2}}]N m−2\text{N m}^{-2}
Universal constant of gravitation (G)(G)G=Fr2m1m2G=\dfrac{Fr^2}{m_1 m_2}[M−1L3T−2][\textcolor{#0a7d73}{\text{M}^{-1}}\textcolor{#1f5fcf}{\text{L}^3}\textcolor{#6a3fcf}{\text{T}^{-2}}]N m2kg−2\text{N m}^2\text{kg}^{-2}
Workforce ×\times distance[M1L2T−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^2}\textcolor{#6a3fcf}{\text{T}^{-2}}]J (joule)
Energy (all types)work[M1L2T−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^2}\textcolor{#6a3fcf}{\text{T}^{-2}}]J (joule)
Moment of forceforce ×\times distance[M1L2T−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^2}\textcolor{#6a3fcf}{\text{T}^{-2}}]N m
Powerwork / time[M1L2T−3][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^2}\textcolor{#6a3fcf}{\text{T}^{-3}}]W (watt)
Surface tensionforce / length[M1L0T−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^0}\textcolor{#6a3fcf}{\text{T}^{-2}}]N m−1\text{N m}^{-1}
Surface energyenergy / area[M1L0T−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^0}\textcolor{#6a3fcf}{\text{T}^{-2}}]J m−2\text{J m}^{-2}
Force constantforce / displacement[M1L0T−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^0}\textcolor{#6a3fcf}{\text{T}^{-2}}]N m−1\text{N m}^{-1}
Thrustforce[M1L1T−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^{-2}}]N (newton)
Tensionforce[M1L1T−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^{-2}}]N (newton)
Stress, pressureforce / area[M1L−1T−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^{-1}}\textcolor{#6a3fcf}{\text{T}^{-2}}]N m−2\text{N m}^{-2}
Strainchange in dimension / original dimension[M0L0T0][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^0}\textcolor{#6a3fcf}{\text{T}^0}]no units
Coefficient of elasticitystress / strain[M1L−1T−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^{-1}}\textcolor{#6a3fcf}{\text{T}^{-2}}]N m−2\text{N m}^{-2}
Radius of gyration (K)(K)distance[M0L1T0][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^0}]m
Moment of inertia (I)(I)mass ×\times (radius of gyration)2^2[M1L2T0][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^2}\textcolor{#6a3fcf}{\text{T}^0}]kg m2\text{kg m}^2
Angle / angular displacement (θ)(\theta)arc / radius[M0L0T0][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^0}\textcolor{#6a3fcf}{\text{T}^0}]radian
Angular velocity (ω)(\omega)angle / time[M0L0T−1][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^0}\textcolor{#6a3fcf}{\text{T}^{-1}}]rad s−1\text{rad s}^{-1}
Angular acceleration (α)(\alpha)change in angular velocity / time[M0L0T−2][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^0}\textcolor{#6a3fcf}{\text{T}^{-2}}]rad s−2\text{rad s}^{-2}
Angular momentumIωI\omega[M1L2T−1][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^2}\textcolor{#6a3fcf}{\text{T}^{-1}}]kg m2s−1\text{kg m}^2\text{s}^{-1}
Torqueforce ×\times distance[M1L2T−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^2}\textcolor{#6a3fcf}{\text{T}^{-2}}]N m
Wavelength (λ)(\lambda)length of one wave (distance)[M0L1T0][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^0}]m
Frequency (ν)(\nu)number of vibrations / time[M0L0T−1][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^0}\textcolor{#6a3fcf}{\text{T}^{-1}}]s−1\text{s}^{-1} or Hz
Angular frequency (ω)(\omega)2π×2\pi\times frequency[M0L0T−1][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^0}\textcolor{#6a3fcf}{\text{T}^{-1}}]rad s−1\text{rad s}^{-1}
Velocity of light in vacuum (c)(c)distance / time[M0L1T−1][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^{-1}}]m s−1\text{m s}^{-1}
Velocity gradientvelocity / distance[M0L0T−1][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^0}\textcolor{#6a3fcf}{\text{T}^{-1}}]s−1\text{s}^{-1}
Rate of flowvolume / time[M0L3T−1][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^3}\textcolor{#6a3fcf}{\text{T}^{-1}}]m3s−1\text{m}^3\text{s}^{-1}
Planck's constant (h)(h)energy / frequency[M1L2T−1][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^2}\textcolor{#6a3fcf}{\text{T}^{-1}}]J s
Linear mass density (m)(m)mass / length[M1L−1T0][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^{-1}}\textcolor{#6a3fcf}{\text{T}^0}]kg m−1\text{kg m}^{-1}
Distance travelled in nnth seconddistance / time[M0L1T−1][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^{-1}}]m s−1\text{m s}^{-1}
Avogadro's number (N)(N)number of molecules per mole[M0L0T0][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^0}\textcolor{#6a3fcf}{\text{T}^0}]mol−1\text{mol}^{-1}
Magnetic dipole moment (M)(M)I×AI\times A (current ×\times area)[M0L2T0A1][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^2}\textcolor{#6a3fcf}{\text{T}^0}\textcolor{#c2570a}{\text{A}^1}]A m2\text{A m}^2
Pole strength (m)(m)m=M2lm=\dfrac{M}{2l}[M0L1T0A1][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^0}\textcolor{#c2570a}{\text{A}^1}]A m
Magnetic permeability of free space (μ0)(\mu_0)μ0=4πFr2m1m2\mu_0=\dfrac{4\pi F r^2}{m_1 m_2}[M1L1T−2A−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^{-2}}\textcolor{#c2570a}{\text{A}^{-2}}]H m−1\text{H m}^{-1}
Resistance (R)(R)potential difference / current[M1L2T−3A−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^2}\textcolor{#6a3fcf}{\text{T}^{-3}}\textcolor{#c2570a}{\text{A}^{-2}}]Ω\Omega (ohm)
Capacitance (C)(C)charge / potential difference[M−1L−2T4A2][\textcolor{#0a7d73}{\text{M}^{-1}}\textcolor{#1f5fcf}{\text{L}^{-2}}\textcolor{#6a3fcf}{\text{T}^4}\textcolor{#c2570a}{\text{A}^2}]F (farad)
Surface density of chargecharge / area[M0L−2T1A1][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^{-2}}\textcolor{#6a3fcf}{\text{T}^1}\textcolor{#c2570a}{\text{A}^1}]C m−2\text{C m}^{-2}
Electric dipole moment (p)(p)q (2d)q\,(2d)[M0L1T1A1][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^1}\textcolor{#6a3fcf}{\text{T}^1}\textcolor{#c2570a}{\text{A}^1}]C m
Specific resistance / resistivity (ρ)(\rho)RAl\dfrac{RA}{l}[M1L3T−3A−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^3}\textcolor{#6a3fcf}{\text{T}^{-3}}\textcolor{#c2570a}{\text{A}^{-2}}]Ω\Omega m
Conductance (G)(G)1/R1/R[M−1L−2T3A2][\textcolor{#0a7d73}{\text{M}^{-1}}\textcolor{#1f5fcf}{\text{L}^{-2}}\textcolor{#6a3fcf}{\text{T}^3}\textcolor{#c2570a}{\text{A}^2}]S (siemens)
Conductivity (σ)(\sigma)1/ρ1/\rho[M−1L−3T3A2][\textcolor{#0a7d73}{\text{M}^{-1}}\textcolor{#1f5fcf}{\text{L}^{-3}}\textcolor{#6a3fcf}{\text{T}^3}\textcolor{#c2570a}{\text{A}^2}]S m−1\text{S m}^{-1}
Electric fluxelectric field ×\times area[M1L3T−3A−1][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^3}\textcolor{#6a3fcf}{\text{T}^{-3}}\textcolor{#c2570a}{\text{A}^{-1}}]N m2C−1\text{N m}^2\text{C}^{-1}
Faraday constantAvogadro number ×\times elementary charge[M0L0T1A1][\textcolor{#0a7d73}{\text{M}^0}\textcolor{#1f5fcf}{\text{L}^0}\textcolor{#6a3fcf}{\text{T}^1}\textcolor{#c2570a}{\text{A}^1}]C mol−1\text{C mol}^{-1}
Mass defect (Δm)(\Delta m)sum of masses of nucleons −- mass of nucleus[M1L0T0][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^0}\textcolor{#6a3fcf}{\text{T}^0}]kg
Binding energy of nucleus(mass defect) ×\times (speed of light)2^2[M1L2T−2][\textcolor{#0a7d73}{\text{M}^1}\textcolor{#1f5fcf}{\text{L}^2}\textcolor{#6a3fcf}{\text{T}^{-2}}]J (joule)

3.3Dimensional Analysis and Its Applications

Dimensional analysis is a quick and powerful tool. It is used to check equations for consistency (homogeneity). It can also find relations between quantities. It has three main uses:

1

Checking whether an equation is dimensionally consistent

see 3.4
2

Converting a value from one system of units to another

see 3.5
3

Finding the relation between physical quantities

see 3.6

3.4Checking the Dimensional Consistency of Equations

Only quantities with the same dimensions can be added or subtracted. For example, a mass cannot be added to a velocity. A current cannot be subtracted from a time. This simple idea gives the principle of homogeneity of dimensions. We use it to test equations.

Principle
Principle of Homogeneity of Dimensions

An equation is dimensionally correct only if every term on both sides has the same dimensions.

e.g. Test the equation of motion   s=ut+12at2\;s = ut + \tfrac{1}{2}at^2. Each term must have the dimensions [L][\textcolor{#1f5fcf}{\text{L}}]:

[s][s]=[L][\textcolor{#1f5fcf}{\text{L}}]✓
[ut][ut]=[LT−1][T]=[L][\textcolor{#1f5fcf}{\text{L}}\textcolor{#6a3fcf}{\text{T}^{-1}}][\textcolor{#6a3fcf}{\text{T}}] = [\textcolor{#1f5fcf}{\text{L}}]✓
[12at2]\left[\tfrac{1}{2}at^2\right]=[LT−2][T2]=[L][\textcolor{#1f5fcf}{\text{L}}\textcolor{#6a3fcf}{\text{T}^{-2}}][\textcolor{#6a3fcf}{\text{T}^2}] = [\textcolor{#1f5fcf}{\text{L}}]✓

ResultEvery term reduces to [L][\textcolor{#1f5fcf}{\text{L}}]. So the equation is dimensionally correct

3.5Conversion of One System of Units into Another

A quantity has the same size in every system of units. Its numerical value is inversely proportional to the size of the unit. So n1u1=n2u2n_1u_1 = n_2u_2, which gives n2=n1u1u2n_2 = \dfrac{n_1u_1}{u_2}. Let the two systems have base units M1,L1,T1M_1,L_1,T_1 and M2,L2,T2M_2,L_2,T_2. Let the quantity have dimensions [MaLbTc][\textcolor{#0a7d73}{\text{M}^a}\textcolor{#1f5fcf}{\text{L}^b}\textcolor{#6a3fcf}{\text{T}^c}]. Then:

Conversion Between Systems n2=n1[M1M2]a[L1L2]b[T1T2]cn_2 = n_1\left[\frac{M_1}{M_2}\right]^a\left[\frac{L_1}{L_2}\right]^b\left[\frac{T_1}{T_2}\right]^c

n1,n2n_1,n_2 = numerical values in the two systems;   a,b,ca,b,c = dimensions of the quantity in mass, length and time

3.6Deducing the Relation among the Physical Quantities

Suppose we know which quantities something depends on. Then dimensions can tell us how it depends on them. Take a simple pendulum. Its time period tt may depend on its length (l)(l), the mass of the bob (m)(m) and the acceleration due to gravity (g)(g).

Derivation
Setup

Assume   t=k ma lb gc…(i)\;t = k\,m^a\,l^b\,g^c\quad\ldots(i). Here kk is a dimensionless constant, and a,b,ca,b,c are the powers to be found.

  1. Write both sides in terms of M, L and T:

    [M0L0T1]=Ma Lb [LT−2]c=Ma Lb+c T−2c[\text{M}^0\text{L}^0\text{T}^1] = \text{M}^a\,\text{L}^b\,[\text{LT}^{-2}]^c = \text{M}^a\,\text{L}^{b+c}\,\text{T}^{-2c}
  2. By the principle of homogeneity, equate the powers of M, L and T on both sides:

    a=0,−2c=1⇒c=−12,b+c=0⇒b=12a=0,\quad -2c = 1 \Rightarrow c = -\tfrac{1}{2},\quad b+c = 0 \Rightarrow b = \tfrac{1}{2}
  3. Put these values of a,b,ca,b,c back into Eq. (i):

    t=k m0 l1/2 g−1/2=klgt = k\,m^0\,l^{1/2}\,g^{-1/2} = k\sqrt{\dfrac{l}{g}}
Time Period of a Simple Pendulum t=klgt = k\sqrt{\dfrac{l}{g}}

kk = dimensionless constant (experiments give k=2πk = 2\pi);   dimensional analysis alone cannot find kk

Problem Solving Strategy
Deriving an Expression

Remember: dimensions can show that an equation is dimensionally valid. But they cannot prove the exact relation between the quantities.

  1. Read the problem carefully. Understand the physics involved.
  2. List the known and the unknown quantities.
  3. Decide which physical principle connects these quantities.
  4. Write the equation that links them. It must agree with the principle you chose.
  5. Solve for the unknowns algebraically first. Substitute numbers only at the next step (except where some terms are zero).
  6. Substitute the known values along with their units. This gives a numerical answer with units.
  7. Check your answer. Are the units right? Is the size of the answer sensible? Compare it with a rough estimate.

3.7Limitations of Dimensional Analysis

✗Limitation 1

It cannot tell us whether a quantity is a scalar or a vector.

✗Limitation 2

It gives no value for dimensionless constants in a formula, such as 1, 2 or π\pi.

✗Limitation 3

It cannot derive formulas that contain trigonometric, logarithmic or exponential functions. These functions have no dimensions.

✗Limitation 4

The method fails if a quantity depends on more than three quantities that have dimensions. This is because comparing the powers of M, L and T gives only three equations.

End of Chapter 1 · notesshala.in
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